Heat capacity of air can be approximately expressed as, Cp = 26.693 + 7.365 x 10^-3 T, where, Cp is in J/mole.K and T is in K. The heat given off by 1 mole of air when cooled at atmospheric pressure from 500°C to - 100°C is ____________________?
Correct answer: C. 18.11 kJ
- A. 10.73 kJ
- B. 16.15 kJ
- C. 18.11 kJ
- D. 18.33 kJ
Explanation
The heat released is obtained by integrating the heat capacity over the temperature drop: Q = 26.693(600) + (7.365 × 10^-3/2)(773.15² − 173.15²), which is about 18.11 kJ per mole. The pressure is irrelevant here because the given heat capacity is Cp and the cooling occurs at atmospheric pressure.
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