Half life of Au-198 is 2.7 days what will be the activity of 1 mg of Au-198
Correct answer: C. 240 Ci
- A. 120 Ci
- B. 200 Ci
- C. 240 Ci
- D. 280 Ci
Explanation
Activity is given as, A= λN, where N is the number of nuclei present in 1 mg of 198Au. Atomic mass of 198Au = 198g
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