Four resistors of equal value are connected in parallel. If the total voltage is 15 V and the total resistance is 600 Ω, the current through each parallel resistor is____________?
Correct answer: C. 6.25 mA
- A. 25 mA
- B. 100 mA
- C. 6.25 mA
- D. 200 mA
Explanation
Four equal parallel resistors have a combined resistance of 600 Ω, so each resistor is 4 × 600 = 2400 Ω. The current in each branch is therefore 15/2400 = 6.25 mA.
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