Four projecties are fired with the same velocity at angle, 25o,40o,55o and 70o with the horizontal. The range of projectile will be largest for the one projected at angle
Correct answer: B. 40o
- A. 70o
- B. 40o
- C. 55o
- D. 25o
Explanation
as R=vi 2 sin20/g all the projectiles have same speed so, R∝sin20 Range will be greater for the angle whose sin20 value will be greater For option A =Sin2(70) =0.64 For option B =Sin2(40) =0.98 For option C =Sin2(55) =0.93 For option D = Sin2(25) =0.76 As 0.98 is the greatest value so range of projectile launched at 40° will be maximum
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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