Force on a proton of charge 2e in a magnetic field of B at 45° while moving with 2 m/s is:
Correct answer: A. 2✓2eB
- A. 2✓2eB
- B. 4eB
- C. 2eB
- D. eB
Explanation
Let's calculate the force:F = (2e) * (2 m/s) * B * sin(45°)Since sin(45°) = √2 / 2, we have:F = (2 * 1.602 x 10^-19 C) * (2 m/s) * B * (√2 / 2)F = (3.204 x 10^-19 C) * (2 m/s) * B * (√2 / 2)F = 4.528 x 10^-19 B N
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Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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