For which equilibrium does Kc has no unit?
Correct answer: B. CH3O(l) + CH3CO2H(l) -> CH2CO2CH2(l) + H2O (l)
- A. C(s) + H2O(g) -> CO(g) +2H2(g)
- B. CH3O(l) + CH3CO2H(l) -> CH2CO2CH2(l) + H2O (l)
- C. Cu2+(aq) + 4NH2(aq) -> Cu(NH2)23+ (aq)
- D. N2O4(g) -> 2NO2
Explanation
The units of Kc are dependent upon the number of moles of (only of gases and liquids, not solids like in option A) reactants and products. If the number of reactants and products becomes equal, Kc will have no unit. For the reaction;CH3OH + CH3CO2H ==> CH₂CO₂CH₂+ H₂OThe number of moles of the reactants and products is the same, i.e. 2, thus Kc has no unit.
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