For the irreversible reaction, Ca+ 2C = Ca C2 , Δ H°298 = - 60000 J . mole-1 . If a system initially containing 2 moles of calcium, 3 moles of carbon and 1 mole of calcium carbide is allowed to react to completion, the heat evolved at 298 K will be__________________?
Correct answer: C. 90,000 J
- A. 30,000 J
- B. 60,000 J
- C. 90,000 J
- D. 2,40,000 J
Explanation
The reaction extent is limited by calcium: 2 mol Ca allows 2 mol of reaction, while 3 mol carbon allows 1.5 mol, so carbon is limiting. Heat evolved is 1.5 × 60,000 = 90,000 J.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? support@testustad.com
Practise Chemical Engineering Thermodynamics
598 free Chemical Engineering Thermodynamics MCQs from Chemical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemical Engineering questions like this
Chemical Engineering is on this paper prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for it.
More Chemical Engineering Thermodynamics questions
When the wet steam is throttled but still remains wet at the exit of the throttle valve, then its temperature & dryness fraction respectively____________________?
Density in the solid state is slightly less than that in its liquid state, in case of____________________?
For an ideal gas, Cp - Cv is____________________?
Dry saturated steam can be converted into super heated steam by____________________?
Rankine cycle comprises of two isothermal and two ___________________ processes?
Thermodynamic cycle involved in the working of a thermal power plant is the ______________ cycle ?