For the gaseous reaction 2X + Y → Z.rate = k [X]2 [Y]0If the pressure in the reaction vessel is doubled but temperature remains constant. By what factor does the rate of reaction increases?
Correct answer: D. 4
- A. 2
- B. 8
- C. 3
- D. 4
Explanation
Option D is correct.The rate of reaction of a gaseous reaction is proportional to the partial pressure of the reactants. In the reaction 2X + Y → Z .The rate of reaction is given by the following equation: rate = k[X]²[Y]⁰ ,where k is the rate constant and [X] and [Y] are the partial pressures of X and Y, respectively.In this case, the concentration of X will be doubled, but the concentration of Y will remain the same. The rate of reaction will increase by a factor of 2² = 4. but the order of reaction is 2.
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Reaction kinetics relates reaction rate to concentration, temperature, surface area and catalysts. Questions cover rate laws, reaction order, rate constants, activation energy and the activated complex, including how a catalyst lowers the activation energy without changing the overall energy change or equilibrium position.
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