For the equations ax + 2y = 4 and 3x + 6y = 12 to have infinitely many solutions, what must be the value of a?
Correct answer: A. 1
- A. 1
- B. 2
- C. 3
- D. 6
Explanation
The second equation is three times the equation x + 2y = 4. Therefore, the first equation must be x + 2y = 4, which requires a = 1.
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