For stable molecular geometry, each carbon atom undergoes:
Correct answer: A. sp hybridization
- A. sp hybridization
- B. sp2 hybridization
- C. sp3 hybridization
- D. dsp3 hybridization
- E. d2sp2 hybridization
Explanation
Carbon can undergo all three hybridization i.e. sp, sp2 and sp3. Carbon can have an sp hybridization when it is bound to two other atoms with the help of two double bonds or one single and one triple bond. This results in linear arrangement and bond angle of 180°. A carbon atom is sp2 hybridized when bonding takes place between 1 s-orbital with two p orbitals. There is a formation of two single bonds and one double bond between three atoms. This reults in trignol arrangement with bond angles of 120° A carbon atom is sp3 hybridized when it is bonded to four other atoms. Here, 1 s orbital and 3 p orbitals in the same shell of an atom combine to form four new equivalent orbitals. This results in is tetrahedral with a bond angle of 109.5° The order of strength of CH bonds is sp>sp2>sp3.
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Chemical bonding explains molecular shape through VSEPR theory and distinguishes sigma bonds from pi bonds. Questions involve hybridization, bond angles, dipole moment and bond energy, including how electron-pair repulsion determines geometry and how bond polarity differs from the overall polarity of a molecule.
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