For every electron that diffuses across a junction and combines with a hole, a positive chargeis left in the X region and a negative charge is created in the Y region forming a potentialbarrier.Considering the given image, the X and Y regions are
Correct answer: D. Option D: X is the N-region, Y is the P-region.
- A. Option A: X is the N-region, Y is the P-region.
- B. Option B: X is the P-region, Y is the N-region.
- C. Option C: X is the cathode, Y is the anode.
- D. Option D: X is the N-region, Y is the P-region.
Explanation
The correct answer is Option D: X is the N-region, Y is the P-region. In a PN junction, electrons naturally move from the N-region, which is electron-rich, to the P-region, which has an abundance of holes. As electrons leave the N-region, they leave behind positively charged ions, resulting in a positive charge in that region. Conversely, the P-region gains electrons, which combine with holes, and this creates a negative charge. This movement of charge carriers forms an electric field that constitutes a potential barrier, preventing further diffusion of charge carriers across the junction.Option A incorrectly describes the regions as reversed, while Option B does not accurately describe the regions in terms of charge distribution. Option C uses terms more applicable to external circuit descriptions, and not for the intrinsic regions of the PN junction.
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About PN Junction
A PN junction forms when p type and n type semiconductor regions meet, creating a depletion layer and a potential barrier. The topic covers forward and reverse bias, diode current voltage characteristics, breakdown and rectification, while distinguishing an ordinary junction diode from a transistor formed from multiple junctions.
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