For an (n) number of capacitors, each with capacitance "C", what will be the ratio between the maximum and minimum capacitances?
Correct answer: A. n2
- A. n2
- B. n
- C. n3
- D. 1
Explanation
The question asks for the ratio of the maximum to minimum capacitance for n capacitors. When n capacitors, each with capacitance C, are connected in series, the equivalent capacitance is minimized and given by Cseries = C/n. Conversely, when they are connected in parallel, the equivalent capacitance is maximized, given by Cparallel = nC. Therefore, the ratio of maximum to minimum capacitance is (nC)/(C/n) = n2.Option A is correct because it accurately depicts the squared relationship in the ratio. Option B incorrectly assumes a linear relationship, Option C overestimates the ratio, and Option D incorrectly suggests no change in capacitance.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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