For a satellite so that it could stay over the same point on Earth's surface the orbital radius r is given by _.
Correct answer: C. r = [GMT2 / 4x2 ] 1/3
- A. r2 = GMT2 / 4x2
- B. r2 = [GMT2 / 4x2 ] 1/3
- C. r = [GMT2 / 4x2 ] 1/3
- D. r = [GMT / 4x2 ] 1/3
Explanation
For a satellite, the gravitational force provides the centripetal force; therefore: Fg=Fc {where Fg is the gravitational force and Fc is the centripetal force} GMm/r2=mv2/r Make R the subject of the equation to obtain: r=[GMT2/4x2]⅓
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About Gravitation
Newton’s law of universal gravitation relates the force between masses to their masses and separation, while gravitational field strength explains weight and orbital motion. The topic covers satellite velocity and period, escape ideas, weightlessness in free fall, and artificial gravity, which differs from ordinary gravitational attraction.
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