FIX THIS:The distance between the slits in young's double slit experiment is 0.25cm. Interference fringes are formed on a screen placed at a distance of 100cm from slits. The distance of the third dark fringe from the central bright fringe is 0...59cm. What is the wavelength of the incident light?
Correct answer: B. 590nm
- A. 390nm
- B. 590nm
- C. 690nm
- D. 790nm
- E. 990nm
Explanation
Given:Distance between the slits (d) = 0.25 cm = 0.0025 mDistance to the screen (D) = 100 cm = 1 mDistance of the third dark fringe (y3) = 0.59 cm = 0.0059 mFor dark fringes in Young's experiment, the position ym is given by:ym=(m+1/2)λD/dλ=y3*d/(m+1/2)Dλ=0.0000059m=590nm
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Light is studied through reflection, refraction, dispersion, interference, diffraction and polarization, linking ray behavior with its wave nature. Questions may involve mirrors, lenses, optical instruments, refractive index and image formation, while geometrical optics deals with rays and wave optics explains effects such as interference and diffraction.
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