Find the maximum force of the conductor having length 60 cm, current 2.75 A, and flux density of 9 units.
Correct answer: A. 14.85
- A. 14.85
- B. 18.45
- C. 84.25
- D. 7.325
Explanation
I= 2.75A , L= 60cm , B= 9Force on a current carrying conductor is given by; F=ILBF=(2.75)(0.6)(9) (60cm=0.6m)F=14.85
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About Electromagnetism
Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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