Find the current passing through the 10 Ω resistor in the figure below.
Correct answer: A. 5/31 A
- A. 5/31 A
- B. 6/31 A
- C. 4/31 A
- D. None of these
Explanation
Using nodal analysis at node b (taking node a as reference with voltage Va = 0), the sum of currents leaving node b is (Vb - 1.5)/1 + (Vb - 2)/1 + (Vb - 1.5)/1 + Vb/10 = 0Combining terms,3Vb - 5 + Vb/10 = 03.1Vb=5Thus,Vb = 5/3.1The current through the 10Ω resistor is I = Vt/10 = 5/(3.1 * 10) = 5/31The correct answer is A. 5/31 A.
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