FeO (s) + CO (g) = Fe (s) + CO2 (g), k = 0. 435 at 1173E; at equilibrium, what will be the number of moles of CO gas required to reduce one mole of FeO at 1173 K ?
Correct answer: D. 3.3
- A. 1.0
- B. 1.3
- C. 2.3
- D. 3.3
Explanation
For FeO + CO ⇌ Fe + CO₂, the equilibrium constant is K = pCO₂/pCO = 0.435 because the solids have unit activity. Reducing one mole produces one mole of CO₂, so the remaining CO is about 2.3 mol and the initial requirement is approximately 3.3 mol.
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