Enthalpy of formation of NH3 is - 46 kJ/kg mole. The enthalpy change for the gaseous reaction, 2NH3 → N2 + 3H2, is equal to _____________ kJ/kg. mole?
Correct answer: B. 92
- A. 46
- B. 92
- C. -23
- D. -92
Explanation
Using formation enthalpies, ΔH for decomposition is [0] − 2(−46) = +92 kJ per stoichiometric reaction as written. The positive sign appears because ammonia is being decomposed into its elements.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
Practise Chemical Engineering Thermodynamics
598 free Chemical Engineering Thermodynamics MCQs from Chemical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemical Engineering questions like this
Chemical Engineering is on this paper prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for it.
More Chemical Engineering Thermodynamics questions
The equilibria relations in a multi-component and multiphase system cannot be calculated with the help of the_______________?
According to Raoult's law, "The vapor pressure exerted by component in a solution is proportional to the mole fraction of that component." Raoult's law is not applicable under the following assumption/condition?
Gases having same reduced temperatures and reduced pressures_________________?
Heat of reaction is not influenced by__________________?
The temperature at which a real gas obeys Boyle's law is termed as the__________________?
Internal energy is independent of the ____________ for an ideal gas?