Electronic configuration of Gold [Au79] is
Correct answer: A. [Xe]4f14, 5d10, 6s1
- A. [Xe]4f14, 5d10, 6s1
- B. [Xe]4f¹⁰f10, 5d¹⁰, 6s²
- C. [Xe]4f14, 5d9, 6s2
- D. [Xe]4f14, 5d10, 6s2
Explanation
Atomic number of Au is 79, its electronic configuration is1s22s22p63s23p63d104s24p64d105s25p64f145d106s1(The electronic configuration of Xe is 1s22s22p63s23p63d104s24p64d105s25p6)Hence electronic configuration of Au79 is [Xe] 4f14, 5d10, 6s1The correct electron configuration of gold (Au79) is:[Xe]4f14, 5d10, 6s1 This configuration represents the filling of electron orbitals in the order of increasing energy levels. The noble gas core notation [Xe] indicates the electron configuration of the noble gas xenon (54 electrons) up to its completed 5p orbital.
Last updated
About Atomic Structure
Atomic structure covers the discovery of the proton, Planck's quantum theory, hydrogen emission spectra and the evidence for quantized energy levels. You will use quantum numbers to describe orbitals, distinguish s, p, d and f orbital shapes, and write electronic configurations, including the correct order of electron filling.
Practise Atomic Structure
922 free Atomic Structure MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
168 O-2 has how many electrons in s-orbitals?
3s2, 3p4 valence shell electronic configuration corresponds to ?
6Y = 2s12P1x2P1y2P1z this is_configuration
A 1-kW radio frequency of 880 KHz. How many quantas per second does it emit?
A 1kW radio transmitter operates at a frequency of 880 kHz. How many quanta per second does it emit?