Electric potential due to a 2µC charge at a distance of one meter is equal to:
Correct answer: D. 1.8 x 10^4 volt
- A. 18 x 10^4 volt
- B. 1.8 x 10^6 volt
- C. 1.8 x 10^9 volt
- D. 1.8 x 10^4 volt
Explanation
V=KQ/r where K= coulomb's constantV=(9*109)*(2*10-6)/1 = 18000 volts = 1.8*104
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