Electric field strength at a point between oppositely charged plates is 'E'. If the distance between plates is reduced to half, what will be the new value of electric intensity?
Correct answer: D. 2E
- A. 4E
- B. E/2
- C. E/4
- D. 2E
Explanation
Between two parallel plates, the electric field strength is given by:E = V/dIf the distance is halved, electric field strength is doubled since both are inversely related.
This question appeared on the UHS MDCAT 2019 paper, which you can sit online with every answer explained.
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About Electric Field Intensity
Electric field intensity is the force acting per unit positive test charge, with direction set by the force on that charge. Work includes fields of point charges, vector superposition, field lines and the relation between field and electric potential. Field intensity must be distinguished from electric force and potential.
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