During the first step of the reduction phase of the Calvin cycle, the following change occurs:
Correct answer: A. 3-phosphoglycerate is phosphorylated to form 1,3-bisphosphoglycerate using ATP
- A. 3-phosphoglycerate is phosphorylated to form 1,3-bisphosphoglycerate using ATP
- B. 1,3-bisphosphoglycerate is reduced to glyceraldehyde-3-phosphate using NADPH
- C. Ribulose-1,5-bisphosphate reacts with carbon dioxide to form 3-phosphoglycerate
- D. Glyceraldehyde-3-phosphate combines to form glucose directly
Explanation
In the first step of the reduction phase of the Calvin cycle, 3-phosphoglycerate is phosphorylated to form 1,3-bisphosphoglycerate using ATP from the light reactions. This step adds energy to the molecule, preparing it for the next reaction where it will be reduced by NADPH to form glyceraldehyde-3-phosphate. The use of ATP in this step marks the beginning of converting the stable product of carbon fixation into a more energy-rich compound needed for sugar synthesis.
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Cellular respiration explains how cells release energy from glucose through glycolysis, the link reaction, Krebs cycle and electron transport chain. It includes ATP production, substrate-level and oxidative phosphorylation, aerobic versus anaerobic respiration, and the roles of mitochondria, oxygen and fermentation in energy transfer.
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More Bioenergetics questions
The Calvin cycle begins when a molecule of CO₂ reacts with a highly reactive phosphorylated five-carbon sugar named:
First phase of Calvin cycle is:
The cyclic series of reactions by which the carbon is fixed and reduced, resulting in the synthesis of sugar, is called:
The assimilatory and reducing powers synthesized in the light reaction of photosynthesis are utilized in:
The phase of the Calvin cycle in which fewer ATPs of the light reaction are used is:
The number of CO₂, NADPH, and ATP molecules, respectively, required for one Calvin cycle is: