During the decay of radioactive isotopes 232X90 to a stable isotope, six α-particles and four β - particles are emitted, what is the atomic number 'Z' and mass number 'A' of the stable isotopes?
Correct answer: D. Z = 82, A = 208
- A. Z = 70, A = 220
- B. Z = 78, A = 212
- C. Z = 82, A = 212
- D. Z = 82, A = 208
Explanation
Z = 82, A = 208: This option suggests that during the decay of the radioactive isotope 232 90X, six α-particles and four β-particles are emitted, resulting in a stable isotope with atomic number (Z) of 82 and mass number (A) of 208. This option is correct as it accurately represents the resulting stable isotopes from the given decay process.
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Atomic nuclei contain protons and neutrons, with nuclear size, mass defect and binding energy describing their stability. The work covers alpha, beta and gamma decay, decay equations, half-life and decay rate, along with radiation safety and medical applications such as imaging, radiotherapy and tracers.
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