Dr. Khan has discovered two isotopes of an element with atomic number 119.The relative abundance of isotopes 119Uue300 and 119Uue305 is 70% and 30%respectively. The average atomic weight of Uue is
Correct answer: A. 301.5 a.m.u
- A. 301.5 a.m.u
- B. 302.5 a.m.u
- C. 303.5 a.m.u
- D. 304.5 a.m.u
Explanation
Dr. Khan has discovered two isotopes of an element with atomic number 119. The relative abundance of isotopes 119Uue300 and 119Uue305 is 70% and 30% respectively. To calculate the average atomic weight of Uue, we use the following formula:Average atomic weight=(Relative abundance of isotope 1×Atomic mass of isotope 1)+(Relative abundance of isotope 2×Atomic mass of isotope 2)Substituting the given values, we get:Average atomic weight=(0.7×300)+(0.3×305)=301.5Therefore, the average atomic weight of Uue is 301.5 a.m.u.
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