Dr. Khan has discovered two isotopes of an element with atomic number 119.The relative abundance of isotopes 119Uue300 and 119Uue305 is 70% and 30%respectively. The average atomic weight of Uue is
Correct answer: A. 301.5 a.m.u
- A. 301.5 a.m.u
- B. 302.5 a.m.u
- C. 303.5 a.m.u
- D. 304.5 a.m.u
Explanation
Dr. Khan has discovered two isotopes of an element with atomic number 119. The relative abundance of isotopes 119Uue300 and 119Uue305 is 70% and 30% respectively. To calculate the average atomic weight of Uue, we use the following formula:Average atomic weight=(Relative abundance of isotope 1×Atomic mass of isotope 1)+(Relative abundance of isotope 2×Atomic mass of isotope 2)Substituting the given values, we get:Average atomic weight=(0.7×300)+(0.3×305)=301.5Therefore, the average atomic weight of Uue is 301.5 a.m.u.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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