Distance covered during one vibration of an oscillating body in terms of amplitude "A" is:

Explanation

During one complete vibration of an oscillating body in simple harmonic motion, the body travels from the equilibrium position to the maximum positive amplitude, returns to the equilibrium, continues to the maximum negative amplitude, and returns to the equilibrium position again. This results in a total distance covered of 4 times the amplitude (4A).Option A (Zero) is incorrect because the body does indeed travel a distance during the cycle. Option B (A) is incorrect because this is only the distance to the maximum displacement in one direction. Option C (2A) is incorrect as it only accounts for the distance traveled to one amplitude and back to equilibrium, which is half of the total cycle.