Critical speed of rotation, N (in rps - rotation per second) of a trammel is equal to (where, g = acceleration due to gravity = 9.81 m/sec2 and, r = radius of trammel, metre.) ?
Correct answer: A. (1/2π). √(g/r)
- A. (1/2π). √(g/r)
- B. (1/π). √(g/r)
- C. ½ √(g/r)
- D. 2π. √(g/r)
Explanation
At critical speed, a particle just remains in circular contact with the trammel wall, giving omega squared r equals g. Since N equals omega divided by 2 pi, N equals (1/2 pi) square root of g/r.
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