Moderate

Consider a peak rectifier fed by a 60-Hz sinusoid having a peak value Vp = 100V. Let the load resistance R = 10kΩ. Calculate the fraction of the cycle during which the diode is conducting:

Correct answer: C. 3.18 %

  • A. 1.06 %
  • B. 2.06 %
  • C. 3.18 %
  • D. 4.82 %

Explanation

The correct answer is Option C: 3.18 %The best I can explain: w Δt ~ √(2Vr/Vp)Θ = √(2 X 2/100)Θ = 0.2 rad or 3.18 % of the cycle.

Last updated

About Electronics

A p-n junction forms when p-type and n-type semiconductor regions meet, creating a depletion layer, barrier potential and rectifying action. The work covers forward and reverse bias, junction current, diode characteristics, and how a diode converts alternating current into pulsating direct current through half-wave and full-wave rectification.

Practise Electronics

660 free Electronics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Exams that ask Physics questions like this

Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

Related questions