Asked in PMC Practice Test 16 (2021) 2021Moderate

Consider a car is travelling for one hour. Whuch of the following trips have the same average velocity?

Correct answer: B. car travels 40 km due east then turns around and travels 20 km due west and car travels 20 km due east

  • A. car travels 20 km due east and car travels 70 km due west.
  • B. car travels 40 km due east then turns around and travels 20 km due west and car travels 20 km due east
  • C. car travels 40 km due east then turns around and travels 20 km due west and car travels 70 km due east
  • D. car travels 30 km due west then turns around and travels 30 km due east and car travels 40 km due east, then turns around and travels 20 km due west

Explanation

Trip A displacement: 40 Km east then 20 km west, in vector form we can say that the car travels +40 then -20. So total displacement will be: +40-20=+20kmTrip B displacement: 200 km east or +20 kmso both are equal. When the displacements are equal and the time is also equal (1 hr), then the average velocity is also equal because V=S/t

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Displacement is the directed change in position, while velocity is the rate of change of displacement and includes both magnitude and direction. The topic connects position-time and velocity-time graphs with average and instantaneous values, and distinguishes displacement from distance and velocity from speed.

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