Consider a car is travelling for one hour. Which of the following trips have the same average velocity?
Correct answer: B. Car travels 40 km due east, then turns around and travels 20 km due west and a car that travels 20 km due east
- A. Car travels 20 km due east and car travels 70 km due east
- B. Car travels 40 km due east, then turns around and travels 20 km due west and a car that travels 20 km due east
- C. Car travels 70 km due east and a car that travels 40 km due east, then turns around and travels 20 km due west
- D. Car travels 30 km due west, then turns around and travels 30 km due east and a car that travels 40 km due east, then turns around and travels 20 km due west
Explanation
Average velocity = total displacement/total timeWe know that displacement is a vector quantity. Therefore, let's assume that the west direction is negative and the east direction is positive throughout this question.For option B:Average velocity of the 1st car = {+40 + (-20)}/1 = 20 km/hrAverage velocity of the 2nd car = +20/1 = 20 km/hrThus B is the correct option.
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