CH3COOH + OH-➞ CH3COO -+ H2O q1,H + OH ➞ H2O q2.The ∆H for CH3COOH ➞ CH3COO † H is
Correct answer: B. q1 - q2
- A. q1 + q2
- B. q1 - q2
- C. q2 - q1
- D. -q1 - q2
Explanation
The enthalpy change for the reaction CH3COOH → CH3COO- + H is the difference between the enthalpy change for the first reaction and the enthalpy change for the second reaction. This is:∆H = q1 - q2.Therefore, the answer is q1 - q2.Explanation is given below.
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About Thermochemistry and Energetics of Chemical Reactions
Thermochemistry measures energy changes in chemical reactions and distinguishes exothermic from endothermic processes. Work covers systems, surroundings and state functions, internal energy, the first law of thermodynamics, enthalpy and Hess's law, including the sign conventions used when heat enters or leaves a system.
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