C12H22O11 + conc. H2SO4 → 12 C + ? + H2SO4
Correct answer: A. 11 H2O
- A. 11 H2O
- B. 11 O2
- C. 11 CO2
- D. 11 H2
Explanation
Comparing reactant and product side we can see that there is a difference of 22 H and 11 O. That means the compound that we can make of it is 11 H2O. Hence the answer is A.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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