Moderate

Atomic number of C is 6 and H is 1. How many electrons are present in 1.6 grams of methane?

Correct answer: A. 6.022 x 10^23 electrons

  • A. 6.022 x 10^23 electrons
  • B. 1.204 x 10^24 electrons
  • C. 3.011 x 10^23 electrons
  • D. 2.409 x 10^24 electrons

Explanation

Determine the molar mass of methane (CH4): The molar mass of CH4 is 12.01 g/mol (for carbon) + 4 * 1.01 g/mol (for hydrogen) = 16.05 g/mol.Calculate the number of moles of methane in 1.6 grams: Number of moles = mass / molar mass = 1.6 g / 16.05 g/mol = 0.0997 moles.Determine the number of molecules of methane: Number of molecules = number of moles * Avogadro's number = 0.0997 moles * 6.022 x 10^23 molecules/mol = 6.022 x 10^22 molecules.Calculate the total number of electrons in one molecule of methane: Each methane molecule has 10 electrons (6 from carbon and 1 from each hydrogen).Calculate the total number of electrons in 6.022 x 10^22 molecules of methane: Total electrons = 6.022 x 10^22 molecules * 10 electrons/molecule = 6.022 x 10^23 electrons. Therefore, there are 6.022 x 10^23 electrons present in 1.6 grams of methane.

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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.

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