Atomic number of C is 6 and H is 1. How many electrons are present in 1.6 grams of methane?
Correct answer: A. 6.022 x 10^23 electrons
- A. 6.022 x 10^23 electrons
- B. 1.204 x 10^24 electrons
- C. 3.011 x 10^23 electrons
- D. 2.409 x 10^24 electrons
Explanation
Determine the molar mass of methane (CH4): The molar mass of CH4 is 12.01 g/mol (for carbon) + 4 * 1.01 g/mol (for hydrogen) = 16.05 g/mol.Calculate the number of moles of methane in 1.6 grams: Number of moles = mass / molar mass = 1.6 g / 16.05 g/mol = 0.0997 moles.Determine the number of molecules of methane: Number of molecules = number of moles * Avogadro's number = 0.0997 moles * 6.022 x 10^23 molecules/mol = 6.022 x 10^22 molecules.Calculate the total number of electrons in one molecule of methane: Each methane molecule has 10 electrons (6 from carbon and 1 from each hydrogen).Calculate the total number of electrons in 6.022 x 10^22 molecules of methane: Total electrons = 6.022 x 10^22 molecules * 10 electrons/molecule = 6.022 x 10^23 electrons. Therefore, there are 6.022 x 10^23 electrons present in 1.6 grams of methane.
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