At what x-value does the quadratic function y = −x² + 6x + 1 attain its maximum?
Correct answer: B. x = 3
- A. x = 2
- B. x = 3
- C. x = 4
- D. x = 6
Explanation
For y = ax² + bx + c, the vertex occurs at x = −b/(2a). Therefore, x = −6/(2 × −1) = 3, where the downward-opening parabola reaches its maximum.
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