At what angle of projection of a projectile does the range become half of its maximum value?
Correct answer: A. 15
- A. 15
- B. 20
- C. 30
- D. 40
Explanation
R=Vi2(sin 2θ)/g At given condition: Maximum range= Rmax= vi2θ/g. For the maximum range, sin2θ=1 which is possible if we put the angle as 45 degrees but to get half of the maximum range we should take θ such that sin2θ is equal to 0.5. It is known that sin 30=0.5 so if we put θ as 15 we will get sin2(15)=sin 30=0.5.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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