At standard conditions of temperature and pressure, the ratio of volume of 18g H2O to the volume of 4.4g CO2 will be:
Correct answer: A. 10:1
- A. 10:1
- B. 1:2
- C. 2:3
- D. 3:2
- E. 2:1
Explanation
No of moles=mass in g/MrMoles of water = 18/18 =1 mol 1mol=24dm3 so volume of water is also 24dm3 Moles of CO2= 4.4/44 = 0.1 moles0.1x24= 2.4dm324:2.410:1
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About Standard Temperature and Pressure
Standard temperature and pressure provide reference conditions for gas calculations: 0°C or 273 K and, in the usual school convention, 1 atm pressure. Questions use these conditions to relate pressure, volume, temperature and amount of gas, including the molar volume of an ideal gas, about 22.4 dm³.
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