At one instant an electron (charge = -1.6 x 10^-19 C) is moving in the xy plane, the components of its velocity being vx = 5 x 10^5 m/s and Vy = 3 x 10^5 m/s. A magnetic field of 0.8 T is in the positive x direction. At that instant the magnitude of the magnetic force on the electron is:
Correct answer: C. 3.8 x 10^-14N
- A. 0
- B. 2.6 x 10^-14N
- C. 3.8 x 10^-14N
- D. 6.4 x 10^-14N
Explanation
For magnetic force only vertical component is responsible
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Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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