At Murree Hills (Assume the value of g changes). If we use a simple pendulum as time standard then one-second duration will_____________?
Correct answer: A. Increase
- A. Increase
- B. Decrease
- C. Remains the same
- D. Is zero
Explanation
The pendulum period is T = 2π√(L/g). At Murree, g is smaller than at the reference location, so T increases for the same length L. Students may choose b by thinking that a smaller gravitational acceleration makes the pendulum swing faster, but it actually makes each swing slower.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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