At equilibrium condition, the chemical potential of a material in different phases in contact with each other is equal. The chemical potential for a real gas (μ) is given by (where, μ = standard chemical potential at unit fugacity (f° = 1 atm.) and the gas behaves ideally.) ?
Correct answer: A. μ° + RT ln f
- A. μ° + RT ln f
- B. μ°+ R ln f
- C. μ° + T ln f
- D. μ° + R/T ln f
Explanation
For a real gas, fugacity replaces pressure in the chemical-potential expression: μ = μ° + RT ln(f/f°). Since the standard fugacity is taken as 1 atm here, this reduces to the form in option a.
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