At a given value of E/R (ratio of activation energy and gas constant), the ratio of the rate constants at 500°K and 400°K is 2, if Arrhenius law is used. What will be this ratio, if transition state theory is used with the same value of „E/R‟ ?
Correct answer: D. 2.5
- A. 1.6
- B. 2
- C. 2.24
- D. 2.5
Explanation
Arrhenius behavior gives k500/k400 = 2, while transition-state theory adds the temperature factor T500/T400 = 1.25. Thus the new ratio is 1.25 × 2 = 2.5.
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