At 100.C and 1 atm, if the density of liquid water is 1.0 g/cc and that of water vapour is 0.0006 g/cc, then the volume occupied by water molecule in one litre of steam at that temperature is:
Correct answer: D. 0.6 cc
- A. 6 cc
- B. 60 cc
- C. 0.06 cc
- D. 0.6 cc
Explanation
The correct answer is D according to the solution given below: Mass of 1L of water vapour = volume x density m=V*d m= 1000 x 0.0006 m= 0.6g Therefore, the volume of liquid water = 0.6/1 V = 0.6cc
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About Ideal Gas Equation
The ideal gas equation, PV = nRT, relates pressure, volume, amount and absolute temperature when gas particles are assumed to have negligible volume and no intermolecular forces. Applications include finding molar mass, density or an unknown gas variable, with careful use of Kelvin temperature and consistent units, and comparison with real-gas behaviour.
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