At 10 kg object collides with stationary 5 kg object and after collision they stick together and move forward with velocity 4ms-1What is the velocity with which the 10 kg object hit the second one?

Explanation

Option A is correct.To determine the velocity with which the 10 kg object hit the second 5 kg object, we can apply the principle of conservation of momentum. According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.The momentum of an object is calculated as the product of its mass and velocity (p = m * v).Let's denote the initial velocity of the 10 kg object as v1 and the initial velocity of the 5 kg object as v2. Since the second object is stationary, its initial velocity is 0 m/s.The total momentum before the collision is given by:Initial momentum = (mass1 * velocity1) + (mass2 * velocity2) = (10 kg * v1) + (5 kg * 0 m/s) = 10 kg * v1After the collision, the two objects stick together and move forward with a velocity of 4 m/s. Let's denote this final velocity as v_f.The total momentum after the collision is given by:Final momentum = (mass1 + mass2) * v_f = (10 kg + 5 kg) * 4 m/s = 15 kg * 4 m/s = 60 kg m/sAccording to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision:10 kg * v1 = 60 kg m/sSolving for v1:v1 = (60 kg m/s) / 10 kgv1 = 6 m/sTherefore, the velocity with which the 10 kg object hit the second 5 kg object is 6 m/s.