As the temperature of black body is raised, the wavelength corresponding to maximum intensity:
Correct answer: B. Shifts towards shorter wavelength
- A. Shifts towards longer wavelength
- B. Shifts towards shorter wavelength
- C. Remains the same
- D. None of these
Explanation
As the temperature of a black body is raised, the wavelength corresponding to the maximum intensity of its emitted radiation decreases. This relationship is described by Wien's displacement law. Specifically, the law states that the product of the temperature and the peak wavelength (λ max) is constant. T . λmax = constant So, as the temperature increases, the wavelength of maximum intensity becomes shorter, and the peak of the emission spectrum shifts toward the shorter-wavelength (blue) end of the electromagnetic spectrum. This phenomenon is observable in various everyday situations, such as observing the color change in a heated metal object (like a stovetop element) from red to blue as its temperature increases.
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Classical physics cannot explain blackbody radiation and related observations, leading to Planck’s quantum theory, in which energy is emitted or absorbed in discrete packets. Photons provide the particle model of light, with energy and momentum linked to frequency and wavelength, including the photoelectric effect and its threshold frequency.
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