As per Newton's law of viscosity, the shear stress for a given rate of angular deformation of fluid is proportional to (where, μ = fluid viscosity) ?
Correct answer: B. μ
- A. 1/μ
- B. μ
- C. μ2
- D. 1/μ2
Explanation
Newton's law states τ = μ(du/dy), so at a fixed rate of angular deformation, shear stress is directly proportional to viscosity μ. It is not proportional to μ² or its reciprocal.
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