An "α" particles enters a magnetic field of strength "B" with a speed "v" parallel to the direction of magnetic field. The force on the particle is:
Correct answer: D. Zero
- A. Bev
- B. Bev/2
- C. Infinite
- D. Zero
Explanation
Speed "v" is parallel to the direction of magnetic field so the angle will be 0 and sin(0) = 0 F = qvBsin0 = 0
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Electromagnetism
Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
Practise Electromagnetism
1,176 free Electromagnetism MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Electromagnetism questions
Magnetic field lines around a current carrying wire are drawn in clockwise direction on a page. The current is flowing:
If current flows in a horizontal straight wire towards East. The direction of magnetic field around it will be:
The unit of permeability of free space is:
A proton entering a uniform magnetic field B in the direction of B will move along a:
A proton moves with a velocity "v" in a perpendicular magnetic field of strength is increased to 2B. If the proton still moves in the same circular path its kinetic energy will:
The figure shows a uniform magnetic field "B" directed to the left and a wire carrying a current into the page. The magnetic force acting on the wire is: