An oxide of metal (M) has 40% mass of oxygen. Metal M has a relative atomic mass of 24. The empirical formula of oxide is
Correct answer: C. MO
- A. M2O
- B. M2O3
- C. MO
- D. M3M4
Explanation
O = 40%no = 40/16no = 2.5 M=60%nM = 60/24nM = 2.5 M: O2.5/2.52.5/2.5MO = Empirical formula
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About Fundamental Concepts of Chemistry
Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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