An organ pipe with both ends open is 0.85 m long. Assuming that the speed of sound is 340 m/s, the frequency of the third harmonic of this pipe is:
Correct answer: D. 600 Hz
- A. 200 Hz
- B. 400 Hz
- C. 300 Hz
- D. 600 Hz
Explanation
For open pipe fn = n v / (2L). n=3 ⇒ f = 3×340/(2×0.85) = 1020/1.7 = 600 Hz. Thus option D is correct.
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About Waves
Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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