An object with an initial velocity of 40m/s moves along a straight axis under constant acceleration. Three seconds later,its velocity is 14m/s. How far did it travel during this time?
Correct answer: A. 81 m
- A. 81 m
- B. 17 m
- C. 67 m
- D. 57 m
- E. 77 m/s
Explanation
To solve for the distance traveled, we first need to determine the acceleration. Using the formula for acceleration (a = (final velocity - initial velocity) / time), we have:a = (14 m/s - 40 m/s) / 3 s = -8.67 m/s².Next, we can use the distance formula:s = ut + 0.5at².Substituting the values:s = (40 m/s * 3 s) + 0.5 * (-8.67 m/s²) * (3 s)² = 120 m - 39 m = 81 m.Therefore, the correct answer is 81 m.The other options do not satisfy the kinematic equations for this scenario.
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