An object of mass 1g is whirled in a horizontal circle of radius 0.5m at a constant speed of 2m/s. The work done on the object during one revolution is:
Correct answer: A. 0
- A. 0
- B. 2 J
- C. 1 J
- D. 4 J
Explanation
W =Fc .dW= Fcd cosθ = Fcd cos90° = Fd (0) = 0Due to centripetal force the object will move in a circular path. In the circular path, the centripetal fore "Fc" is perpendicular to velocity "v". As the displacement "d" is parallel so the velocity "v". So the angle between the displacement "d" and the centripetal force "Fc" is 90o.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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