An object is undergoing simple harmonic motion. Its time period is T and total energy is E. The amplitude of vibration is reduced to half. What is the new time period and total energy of the system?
Correct answer: B. Time period = no change total energy = E/4
- A. Time period = T/2 total energy = E/4
- B. Time period = no change total energy = E/4
- C. Time period= T/2 total energy = E/2
- D. Time period= T total energy= E/2
Explanation
The time period does not depend on the amplitude but only on frequency. However, total energy varies proportionally to the square of the amplitude. So if amplitude reduces by half, energy reduces to (1/2)2 = 1/4
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
Practise Waves
1,281 free Waves MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Simple Harmonic Motion questions
An angular velocity of 60 revolutions per minute is the same as:
In a mass-spring system, which of the following does not depend on the initial displacement of the spring?
Acceleration in the simple pendulum is always _ to displacement.
Under the action of the restoring force:
Calculate the frequency if the number of revolutions is 300 per second and the paired poles are 50.
The potential energy at the mean position of a pendulum is: