An object is thrown vertically upward with a certain initial velocity in a planet where the acceleration due to gravity is 19.6 m/s2. The height to which it raises is _ that which the object would rise if thrown upward with the same initial velocity on the Earth. Neglect friction.
Correct answer: A. Half
- A. Half
- B. Twice
- C. √2 times
- D. Four times
Explanation
To solve this problem, we use the equation for the maximum height reached by an object thrown vertically upward: h = v02 / (2g), where v0 is the initial velocity and g is the acceleration due to gravity. On Earth, assume g = 9.8 m/s2. On the other planet, g = 19.6 m/s2.Thus, the ratio of the heights is:hplanet / hearth = (v02 / (2 * 19.6)) / (v02 / (2 * 9.8)) = 1/2Therefore, the height reached on the other planet is half of that on Earth. The correct answer is Half. The other options are incorrect as they do not correctly reflect the inverse relationship between gravitational acceleration and maximum height.
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